Optimal. Leaf size=222 \[ -\frac {\sqrt {2} a^2 \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}+\frac {\sqrt {2} a^2 \text {ArcTan}\left (1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}+\frac {a^2 \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}-\frac {a^2 \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}+\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f} \]
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Rubi [A]
time = 0.14, antiderivative size = 222, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 11, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.440, Rules used = {3624, 12, 16,
3557, 335, 303, 1176, 631, 210, 1179, 642} \begin {gather*} -\frac {\sqrt {2} a^2 \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}+\frac {\sqrt {2} a^2 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}+1\right )}{\sqrt {d} f}+\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\frac {a^2 \log \left (\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}+\sqrt {d}\right )}{\sqrt {2} \sqrt {d} f}-\frac {a^2 \log \left (\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}+\sqrt {d}\right )}{\sqrt {2} \sqrt {d} f} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 16
Rule 210
Rule 303
Rule 335
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 3557
Rule 3624
Rubi steps
\begin {align*} \int \frac {(a+a \tan (e+f x))^2}{\sqrt {d \tan (e+f x)}} \, dx &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\int \frac {2 a^2 \tan (e+f x)}{\sqrt {d \tan (e+f x)}} \, dx\\ &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\left (2 a^2\right ) \int \frac {\tan (e+f x)}{\sqrt {d \tan (e+f x)}} \, dx\\ &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\frac {\left (2 a^2\right ) \int \sqrt {d \tan (e+f x)} \, dx}{d}\\ &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\frac {\left (2 a^2\right ) \text {Subst}\left (\int \frac {\sqrt {x}}{d^2+x^2} \, dx,x,d \tan (e+f x)\right )}{f}\\ &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\frac {\left (4 a^2\right ) \text {Subst}\left (\int \frac {x^2}{d^2+x^4} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{f}\\ &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}-\frac {\left (2 a^2\right ) \text {Subst}\left (\int \frac {d-x^2}{d^2+x^4} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{f}+\frac {\left (2 a^2\right ) \text {Subst}\left (\int \frac {d+x^2}{d^2+x^4} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{f}\\ &=\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\frac {a^2 \text {Subst}\left (\int \frac {1}{d-\sqrt {2} \sqrt {d} x+x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{f}+\frac {a^2 \text {Subst}\left (\int \frac {1}{d+\sqrt {2} \sqrt {d} x+x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{f}+\frac {a^2 \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {d}+2 x}{-d-\sqrt {2} \sqrt {d} x-x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}+\frac {a^2 \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {d}-2 x}{-d+\sqrt {2} \sqrt {d} x-x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}\\ &=\frac {a^2 \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}-\frac {a^2 \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}+\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}+\frac {\left (\sqrt {2} a^2\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}-\frac {\left (\sqrt {2} a^2\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}\\ &=-\frac {\sqrt {2} a^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}+\frac {\sqrt {2} a^2 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {d} f}+\frac {a^2 \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}-\frac {a^2 \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} \sqrt {d} f}+\frac {2 a^2 \sqrt {d \tan (e+f x)}}{d f}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in
optimal.
time = 0.26, size = 53, normalized size = 0.24 \begin {gather*} \frac {2 a^2 \sqrt {d \tan (e+f x)} \left (3+2 \, _2F_1\left (\frac {3}{4},1;\frac {7}{4};-\tan ^2(e+f x)\right ) \tan (e+f x)\right )}{3 d f} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.22, size = 155, normalized size = 0.70
method | result | size |
derivativedivides | \(\frac {2 a^{2} \left (\sqrt {d \tan \left (f x +e \right )}+\frac {d \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{4 \left (d^{2}\right )^{\frac {1}{4}}}\right )}{f d}\) | \(155\) |
default | \(\frac {2 a^{2} \left (\sqrt {d \tan \left (f x +e \right )}+\frac {d \sqrt {2}\, \left (\ln \left (\frac {d \tan \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \tan \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )-2 \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \tan \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )\right )}{4 \left (d^{2}\right )^{\frac {1}{4}}}\right )}{f d}\) | \(155\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.51, size = 183, normalized size = 0.82 \begin {gather*} \frac {a^{2} d {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {d} + 2 \, \sqrt {d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {d}}\right )}{\sqrt {d}} + \frac {2 \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {d} - 2 \, \sqrt {d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {d}}\right )}{\sqrt {d}} - \frac {\sqrt {2} \log \left (d \tan \left (f x + e\right ) + \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} + d\right )}{\sqrt {d}} + \frac {\sqrt {2} \log \left (d \tan \left (f x + e\right ) - \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {d} + d\right )}{\sqrt {d}}\right )} + 4 \, \sqrt {d \tan \left (f x + e\right )} a^{2}}{2 \, d f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 671 vs.
\(2 (184) = 368\).
time = 1.15, size = 671, normalized size = 3.02 \begin {gather*} -\frac {4 \, \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} d f \arctan \left (-\frac {\sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} a^{6} f \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} + a^{8} - \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} f \sqrt {\frac {a^{12} d \sin \left (f x + e\right ) + \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {3}{4}} a^{6} d^{2} f^{3} \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) + \sqrt {\frac {a^{8}}{d^{2} f^{4}}} a^{8} d^{2} f^{2} \cos \left (f x + e\right )}{\cos \left (f x + e\right )}}}{a^{8}}\right ) + 4 \, \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} d f \arctan \left (-\frac {\sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} a^{6} f \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} - a^{8} - \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} f \sqrt {\frac {a^{12} d \sin \left (f x + e\right ) - \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {3}{4}} a^{6} d^{2} f^{3} \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) + \sqrt {\frac {a^{8}}{d^{2} f^{4}}} a^{8} d^{2} f^{2} \cos \left (f x + e\right )}{\cos \left (f x + e\right )}}}{a^{8}}\right ) + \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} d f \log \left (\frac {a^{12} d \sin \left (f x + e\right ) + \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {3}{4}} a^{6} d^{2} f^{3} \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) + \sqrt {\frac {a^{8}}{d^{2} f^{4}}} a^{8} d^{2} f^{2} \cos \left (f x + e\right )}{\cos \left (f x + e\right )}\right ) - \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {1}{4}} d f \log \left (\frac {a^{12} d \sin \left (f x + e\right ) - \sqrt {2} \left (\frac {a^{8}}{d^{2} f^{4}}\right )^{\frac {3}{4}} a^{6} d^{2} f^{3} \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) + \sqrt {\frac {a^{8}}{d^{2} f^{4}}} a^{8} d^{2} f^{2} \cos \left (f x + e\right )}{\cos \left (f x + e\right )}\right ) - 4 \, a^{2} \sqrt {\frac {d \sin \left (f x + e\right )}{\cos \left (f x + e\right )}}}{2 \, d f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} a^{2} \left (\int \frac {1}{\sqrt {d \tan {\left (e + f x \right )}}}\, dx + \int \frac {2 \tan {\left (e + f x \right )}}{\sqrt {d \tan {\left (e + f x \right )}}}\, dx + \int \frac {\tan ^{2}{\left (e + f x \right )}}{\sqrt {d \tan {\left (e + f x \right )}}}\, dx\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.66, size = 222, normalized size = 1.00 \begin {gather*} \frac {\sqrt {2} a^{2} {\left | d \right |}^{\frac {3}{2}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {{\left | d \right |}} + 2 \, \sqrt {d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {{\left | d \right |}}}\right )}{d^{2} f} + \frac {\sqrt {2} a^{2} {\left | d \right |}^{\frac {3}{2}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {{\left | d \right |}} - 2 \, \sqrt {d \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {{\left | d \right |}}}\right )}{d^{2} f} - \frac {\sqrt {2} a^{2} {\left | d \right |}^{\frac {3}{2}} \log \left (d \tan \left (f x + e\right ) + \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {{\left | d \right |}} + {\left | d \right |}\right )}{2 \, d^{2} f} + \frac {\sqrt {2} a^{2} {\left | d \right |}^{\frac {3}{2}} \log \left (d \tan \left (f x + e\right ) - \sqrt {2} \sqrt {d \tan \left (f x + e\right )} \sqrt {{\left | d \right |}} + {\left | d \right |}\right )}{2 \, d^{2} f} + \frac {2 \, \sqrt {d \tan \left (f x + e\right )} a^{2}}{d f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.06, size = 86, normalized size = 0.39 \begin {gather*} \frac {2\,a^2\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{d\,f}+\frac {2\,{\left (-1\right )}^{1/4}\,a^2\,\mathrm {atan}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{\sqrt {d}}\right )}{\sqrt {d}\,f}-\frac {2\,{\left (-1\right )}^{1/4}\,a^2\,\mathrm {atanh}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{\sqrt {d}}\right )}{\sqrt {d}\,f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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